33 Two cylinders, one containing 1 mole of C4H10 gas at 1 atm and the other containing 1 mole of CH4 gas at 1 atm, are at 288K. If each gas absords 100J of heat under conditions of constant volume, which of the following is true?
A the temoerature of the CH4 increases more than the temperature of the C4H10
B the internal energy of both the CH4 and the C4H10 decrease
C the heat capacyty of the C4H10 is less than the heat capacity of the CH4
D the entropy of both the CH4 and C4H10 decrease
E the heat transferred to the C4H10 is greater than the heat transferred to CH4.
as to option B, internal energy (U) is only a function of temperture (T). Obviously when a system absorbs heat, T will raise.
as to option D, we have: dU=TdS-PdV=TdS, U=Q+W=Q
therefore, dU=TdS
since T increases, the entropy (S) for both gases also increases.
option E is clearly a wrong answer
So by using the process of elimination we got two left: A and C, and they're contradictory to each other.
I wiki the term "temperature" and took a piece of excerpt:
"A diatomic gas, with extra degrees of freedom rotation and vibration, will require a higher energy input to change the temperature by a certain amount, i.e. it will have a higher heat capacity than a monatomic gas."
Probably we can put this into the explanation of the above question, because butane (C4H10) does have larger molecular size and deserves to consume more heat to raise equivalent T as methane (CH4)